What is the derivative of sin(3x-2) ?

The derivative of sin(3x-2) is cos(3x-2)*3

What is the first derivative of sin(3x-2) ?

The first derivative of sin(3x-2) is cos(3x-2)*3

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\frac{d}{d x} (sin (3 x - 2))

cos (3 x - 2) \cdot 3

Solution steps

\frac{d}{d x} (sin (3 x - 2))

Apply the chain rule:

cos (3 x - 2) \frac{d}{d x} (3 x - 2)

= cos (3 x - 2) \frac{d}{d x} (3 x - 2)

\frac{d}{d x} (3 x - 2) = 3

= cos (3 x - 2) \cdot 3

\int (- 2 x^{2}) d x

\int \frac{62 x ^{9}}{2835} d x

x \to 1 + lim (\frac{1}{x ^{2} - 4 x + 3})

\frac{\partial}{\partial x} (tan (x^{3} + y))

\int 5 arcsin (x) d x

What is the derivative of sin(3x-2) ?
The derivative of sin(3x-2) is cos(3x-2)*3
What is the first derivative of sin(3x-2) ?
The first derivative of sin(3x-2) is cos(3x-2)*3