What is the derivative of f(x)= 1/5 (9x+8)^3 ?

The derivative of f(x)= 1/5 (9x+8)^3 is (27(9x+8)^2)/5

What is the first derivative of f(x)= 1/5 (9x+8)^3 ?

The first derivative of f(x)= 1/5 (9x+8)^3 is (27(9x+8)^2)/5

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derivative of

f (x) = \frac{1}{5} (9 x + 8)^{3}

\frac{27 ( 9 x + 8 ) ^{2}}{5}

Solution steps

\frac{d}{d x} (\frac{1}{5} (9 x + 8)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} ((9 x + 8)^{3})

Apply the chain rule:

3 (9 x + 8)^{2} \frac{d}{d x} (9 x + 8)

= 3 (9 x + 8)^{2} \frac{d}{d x} (9 x + 8)

\frac{d}{d x} (9 x + 8) = 9

= \frac{1}{5} \cdot 3 (9 x + 8)^{2} \cdot 9

Simplify

\frac{1}{5} \cdot 3 (9 x + 8)^{2} \cdot 9 : \frac{27 ( 9 x + 8 ) ^{2}}{5}

= \frac{27 ( 9 x + 8 ) ^{2}}{5}

\frac{d}{d x} (- 7 ln (x))

\int (sin^{4} (x)) d x

x \to 1 lim (2 x^{2} - 4 x + 7)

\frac{10}{16 s ^{2} + 5 s + 1}

\frac{\partial}{\partial x} (x^{2} + 4 y^{2} + 5 z^{2})

What is the derivative of f(x)= 1/5 (9x+8)^3 ?
The derivative of f(x)= 1/5 (9x+8)^3 is (27(9x+8)^2)/5
What is the first derivative of f(x)= 1/5 (9x+8)^3 ?
The first derivative of f(x)= 1/5 (9x+8)^3 is (27(9x+8)^2)/5