What is the limit as x approaches+0 of x*+| 1/x | ?

The limit as x approaches+0 of x*+| 1/x | is infinity

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limit as x approaches+0 of x*+| 1/x |

x \to + 0 lim (x \cdot + \frac{1}{x})

\infty

Solution steps

x \to 0 lim (x + \frac{1}{x})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (x + \frac{1}{x}) = \infty

x \to 0 + lim (x + \frac{1}{x}) = \infty

= \infty

\frac{d}{d x} (e^{c o s h (2 x)})

x \to 1 + lim (f (x))

\frac{ln ( cos ( 2 x ) )}{5 x}

\frac{( x - 9 )}{( 5 x - 1 )}, at x = 1

(x - 6)^{2}

What is the limit as x approaches+0 of x*+| 1/x | ?
The limit as x approaches+0 of x*+| 1/x | is infinity