What is the derivative of 3/(x^2-2) ?

The derivative of 3/(x^2-2) is -(6x)/((x^2-2)^2)

What is the first derivative of 3/(x^2-2) ?

The first derivative of 3/(x^2-2) is -(6x)/((x^2-2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{3}{x ^{2} - 2})

- \frac{6 x}{( x ^{2} - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{2} - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{2} - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x^{2} - 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 2 ) ^{2}} \frac{d}{d x} (x^{2} - 2)

= - \frac{1}{( x ^{2} - 2 ) ^{2}} \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= 3 (- \frac{1}{( x ^{2} - 2 ) ^{2}} \cdot 2 x)

Simplify

3 (- \frac{1}{( x ^{2} - 2 ) ^{2}} \cdot 2 x) : - \frac{6 x}{( x ^{2} - 2 ) ^{2}}

= - \frac{6 x}{( x ^{2} - 2 ) ^{2}}

\int_{0}^{2 π} 2

\frac{20}{( s - 4 ) ( s ^{2} + 4 )}

\frac{\partial}{\partial x} ((e^{x} - x) sin (y))

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}, y (1) = 2

x \to 1 lim (x (x + 1))

What is the derivative of 3/(x^2-2) ?
The derivative of 3/(x^2-2) is -(6x)/((x^2-2)^2)
What is the first derivative of 3/(x^2-2) ?
The first derivative of 3/(x^2-2) is -(6x)/((x^2-2)^2)