What is the integral of 36-(0.6x^2+2x+11) ?

The integral of 36-(0.6x^2+2x+11) is -0.2x^3-x^2+25x+C

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integral of 36-(0.6x^2+2x+11)

\int 36 - (0.6 x^{2} + 2 x + 11) d x

- 0.2 x^{3} - x^{2} + 25 x + C

Solution steps

\int 36 - (0.6 x^{2} + 2 x + 11) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 36 d x - \int 0.6 x^{2} + 2 x + 11 d x

\int 36 d x = 36 x

\int 0.6 x^{2} + 2 x + 11 d x = 0.2 x^{3} + x^{2} + 11 x

= 36 x - (0.2 x^{3} + x^{2} + 11 x)

Simplify

= - 0.2 x^{3} - x^{2} + 25 x

Add a constant to the solution

= - 0.2 x^{3} - x^{2} + 25 x + C

\int_{0}^{\frac{π}{2}} 1 - 4 sin^{2} (x) d x

2 x^{- \frac{3}{4}}

\frac{d y}{d x} = (1 + e^{x^{2}}) (5 + x)

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

\frac{d}{d x} (x e^{(- x^{2})})

What is the integral of 36-(0.6x^2+2x+11) ?
The integral of 36-(0.6x^2+2x+11) is -0.2x^3-x^2+25x+C