What is the derivative of-2x^2y ?

The derivative of-2x^2y is -2(2xy+(dy)/(dx)x^2)

What is the first derivative of-2x^2y ?

The first derivative of-2x^2y is -2(2xy+(dy)/(dx)x^2)

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\frac{d}{d x} (- 2 x^{2} y)

- 2 (2 x y + \frac{d y}{d x} x^{2})

Solution steps

\frac{d}{d x} (- 2 x^{2} y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x^{2} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = y

= - 2 (\frac{d}{d x} (x^{2}) y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - 2 (2 x y + \frac{d y}{d x} x^{2})

y^{^{'}} = y (x y^{4} + 1)

\int \frac{x + 1}{9 - x ^{2}} d x

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What is the derivative of-2x^2y ?
The derivative of-2x^2y is -2(2xy+(dy)/(dx)x^2)
What is the first derivative of-2x^2y ?
The first derivative of-2x^2y is -2(2xy+(dy)/(dx)x^2)