What is the derivative of f(x)=sqrt(x)-(x+1)^4 ?

The derivative of f(x)=sqrt(x)-(x+1)^4 is 1/(2sqrt(x))-4(x+1)^3

What is the first derivative of f(x)=sqrt(x)-(x+1)^4 ?

The first derivative of f(x)=sqrt(x)-(x+1)^4 is 1/(2sqrt(x))-4(x+1)^3

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derivative of

f (x) = x - (x + 1)^{4}

\frac{1}{2 x} - 4 (x + 1)^{3}

Solution steps

\frac{d}{d x} (x - (x + 1)^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) - \frac{d}{d x} ((x + 1)^{4})

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} ((x + 1)^{4}) = 4 (x + 1)^{3}

= \frac{1}{2 x} - 4 (x + 1)^{3}

y^{^{'}} = x - 7

e^{x} (4 - x)

\int \frac{9 r ^{2}}{1 - r ^{3}} d r

n = 1 \sum \infty n^{3} e^{- n^{2}}

x \to - 1 lim (\frac{x + 1}{x ^{2} + 1})

What is the derivative of f(x)=sqrt(x)-(x+1)^4 ?
The derivative of f(x)=sqrt(x)-(x+1)^4 is 1/(2sqrt(x))-4(x+1)^3
What is the first derivative of f(x)=sqrt(x)-(x+1)^4 ?
The first derivative of f(x)=sqrt(x)-(x+1)^4 is 1/(2sqrt(x))-4(x+1)^3