What is the derivative of y=3x^{3/8} ?

The derivative of y=3x^{3/8} is 9/(8x^{5/8)}

What is the first derivative of y=3x^{3/8} ?

The first derivative of y=3x^{3/8} is 9/(8x^{5/8)}

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derivative of

y = 3 x^{\frac{3}{8}}

\frac{9}{8 x ^{\frac{5}{8}}}

Solution steps

\frac{d}{d x} (3 x^{\frac{3}{8}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{\frac{3}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot \frac{3}{8} x^{\frac{3}{8} - 1}

Simplify

3 \cdot \frac{3}{8} x^{\frac{3}{8} - 1} : \frac{9}{8 x ^{\frac{5}{8}}}

= \frac{9}{8 x ^{\frac{5}{8}}}

\frac{d y}{d x} = (1 + y) (1 - 2 x)

\int \frac{9 x}{( x + 3 ) ^{2}} d x

\int (\frac{2}{x ^{5}}) d x

\int \frac{4 x - 1}{x ^{2} - 25} d x

5 x^{4} - x^{6}

What is the derivative of y=3x^{3/8} ?
The derivative of y=3x^{3/8} is 9/(8x^{5/8)}
What is the first derivative of y=3x^{3/8} ?
The first derivative of y=3x^{3/8} is 9/(8x^{5/8)}