What is the derivative of f(x)=-2xe^{-x^2} ?

The derivative of f(x)=-2xe^{-x^2} is -2(e^{-x^2}-2e^{-x^2}x^2)

What is the first derivative of f(x)=-2xe^{-x^2} ?

The first derivative of f(x)=-2xe^{-x^2} is -2(e^{-x^2}-2e^{-x^2}x^2)

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derivative of

f (x) = - 2 x e^{- x^{2}}

- 2 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

Solution steps

\frac{d}{d x} (- 2 x e^{- x^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x e^{- x^{2}})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- x^{2}}

= - 2 (\frac{d x}{d x} e^{- x^{2}} + \frac{d}{d x} (e^{- x^{2}}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- x^{2}}) = - 2 e^{- x^{2}} x

= - 2 (1 \cdot e^{- x^{2}} + (- 2 e^{- x^{2}} x) x)

Simplify

- 2 (1 \cdot e^{- x^{2}} + (- 2 e^{- x^{2}} x) x) : - 2 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

= - 2 (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

\int \frac{1}{( y - 1 ) ^{2}} d y

z \to 2 πi lim (e^{z} - e^{- z})

\int_{4}^{6} \frac{1}{t ^{2} - 9} d t

\frac{d}{d x} (\frac{1}{1 + y ^{2}} + cos (x) - 2 x y)

4 e^{x - 3}

What is the derivative of f(x)=-2xe^{-x^2} ?
The derivative of f(x)=-2xe^{-x^2} is -2(e^{-x^2}-2e^{-x^2}x^2)
What is the first derivative of f(x)=-2xe^{-x^2} ?
The first derivative of f(x)=-2xe^{-x^2} is -2(e^{-x^2}-2e^{-x^2}x^2)