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Popular >

integral of 1/(x^2)-1

Solution

\int \frac{1}{x ^{2}} - 1 d x

Solution

- \frac{1}{x} - x + C

Solution steps

\int \frac{1}{x ^{2}} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ^{2}} d x - \int 1 d x

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

\int 1 d x = x

= - \frac{1}{x} - x

Add a constant to the solution

= - \frac{1}{x} - x + C

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Frequently Asked Questions (FAQ)

What is the integral of 1/(x^2)-1 ?
The integral of 1/(x^2)-1 is -1/x-x+C