What is the solution for (dy)/(dx)=-3+2/1 (dy)/(dx) ?

The solution for (dy)/(dx)=-3+2/1 (dy)/(dx) is y=3x+c_{1}

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(dy)/(dx)=-3+2/1 (dy)/(dx)

\frac{d y}{d x} = - 3 + \frac{2}{1} \frac{d y}{d x}

y = 3 x + c_{1}

Solution steps

\frac{d y}{d x} = - 3 + \frac{2}{1} \frac{d y}{d x}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = - 3 + \frac{2}{1} y^{^{'}} (x)

Simplify

y^{^{'}} (x) = 3

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 d x

\int 3 d x = 3 x + c_{1}

y = 3 x + c_{1}

f (x) = 15 x ln (4 x)

\frac{d}{d x} (\frac{7 - x e ^{x}}{x + e ^{x}})

\frac{( s - 1 )}{2 s ^{2} + 8 s + 11}

\int \frac{e ^{x - 5} - e ^{3 + x}}{e ^{1 - x}} d x

f (x) = (1 + 8 x^{2}) (x - x^{2})

What is the solution for (dy)/(dx)=-3+2/1 (dy)/(dx) ?
The solution for (dy)/(dx)=-3+2/1 (dy)/(dx) is y=3x+c_{1}