What is the limit as x approaches 3 of 1/(x^2-9) ?

The limit as x approaches 3 of 1/(x^2-9) is diverges

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limit as x approaches 3 of 1/(x^2-9)

x \to 3 lim (\frac{1}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{1}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{1}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{1}{x ^{2} - 9}) = - \infty

= diverges

t \to π lim (tan (\frac{t}{6}))

\int_{1}^{5} \frac{x ^{2} + 1}{6 x - x ^{2}} d x

\frac{d}{d x} (6 x^{2} - 8 + 40 cos (π) x)

\int \frac{x ^{3}}{1 + x ^{2}} d x

\frac{d}{d x} (\frac{2 x + 1}{x})

What is the limit as x approaches 3 of 1/(x^2-9) ?
The limit as x approaches 3 of 1/(x^2-9) is diverges