What is the derivative of f(x)=sqrt(x^2-3x) ?

The derivative of f(x)=sqrt(x^2-3x) is (2x-3)/(2sqrt(x^2-3x))

What is the first derivative of f(x)=sqrt(x^2-3x) ?

The first derivative of f(x)=sqrt(x^2-3x) is (2x-3)/(2sqrt(x^2-3x))

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derivative of

f (x) = x^{2} - 3 x

\frac{2 x - 3}{2 x ^{2} - 3 x}

Solution steps

\frac{d}{d x} (x^{2} - 3 x)

Apply the chain rule:

\frac{1}{2 x ^{2} - 3 x} \frac{d}{d x} (x^{2} - 3 x)

= \frac{1}{2 x ^{2} - 3 x} \frac{d}{d x} (x^{2} - 3 x)

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

= \frac{1}{2 x ^{2} - 3 x} (2 x - 3)

Simplify

\frac{1}{2 x ^{2} - 3 x} (2 x - 3) : \frac{2 x - 3}{2 x ^{2} - 3 x}

= \frac{2 x - 3}{2 x ^{2} - 3 x}

\frac{d}{d x} (\frac{x - 7 x x}{x})

f (x) = 5 x^{2} cos (x) + x

f (x) = e^{x} + x e^{x}

\int x^{3} in x d x

\frac{\partial}{\partial Q} (Q^{2})

What is the derivative of f(x)=sqrt(x^2-3x) ?
The derivative of f(x)=sqrt(x^2-3x) is (2x-3)/(2sqrt(x^2-3x))
What is the first derivative of f(x)=sqrt(x^2-3x) ?
The first derivative of f(x)=sqrt(x^2-3x) is (2x-3)/(2sqrt(x^2-3x))