What is the derivative of y=x^{8x} ?

The derivative of y=x^{8x} is 8x^{8x}(ln(x)+1)

What is the first derivative of y=x^{8x} ?

The first derivative of y=x^{8x} is 8x^{8x}(ln(x)+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{8 x}

8 x^{8 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (x^{8 x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{8 x} = e^{8 x l n (x)}

= \frac{d}{d x} (e^{8 x l n (x)})

Apply the chain rule:

e^{8 x l n (x)} \frac{d}{d x} (8 x ln (x))

= e^{8 x l n (x)} \frac{d}{d x} (8 x ln (x))

\frac{d}{d x} (8 x ln (x)) = 8 (ln (x) + 1)

= e^{8 x l n (x)} \cdot 8 (ln (x) + 1)

e^{8 x l n (x)} = x^{8 x}

= 8 x^{8 x} (ln (x) + 1)

\frac{\partial}{\partial x} (e^{s i n (x + y)})

f (x) = \frac{( x + 1 )}{( x - 1 )}

\int 17 cot^{4} (x) d x

What is the derivative of y=x^{8x} ?
The derivative of y=x^{8x} is 8x^{8x}(ln(x)+1)
What is the first derivative of y=x^{8x} ?
The first derivative of y=x^{8x} is 8x^{8x}(ln(x)+1)