What is (\partial)/(\partial u)(4ucos(v)) ?

The answer to (\partial)/(\partial u)(4ucos(v)) is 4cos(v)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial u)(4ucos(v))

\frac{\partial}{\partial u} (4 u cos (v))

4 cos (v)

Solution steps

\frac{\partial}{\partial u} (4 u cos (v))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 cos (v) \frac{\partial}{\partial u} (u)

Apply the common derivative:

\frac{\partial}{\partial u} (u) = 1

= 4 cos (v) \cdot 1

Simplify

= 4 cos (v)

\int 2 x^{2} - 2 x^{- 1} d x

\frac{\partial}{\partial y} (6 x y - 12)

\frac{\partial}{\partial x} (2 x^{2} + 3 x y)

\int \frac{1}{100} d x

What is (\partial)/(\partial u)(4ucos(v)) ?
The answer to (\partial)/(\partial u)(4ucos(v)) is 4cos(v)