What is the derivative of (h^2-2h+5)/8 ?

The derivative of (h^2-2h+5)/8 is (h-1)/4

What is the first derivative of (h^2-2h+5)/8 ?

The first derivative of (h^2-2h+5)/8 is (h-1)/4

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derivative of

\frac{h ^{2} - 2 h + 5}{8}

\frac{h - 1}{4}

Solution steps

\frac{d}{d h} (\frac{h ^{2} - 2 h + 5}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d h} (h^{2} - 2 h + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{8} (\frac{d}{d h} (h^{2}) - \frac{d}{d h} (2 h) + \frac{d}{d h} (5))

\frac{d}{d h} (h^{2}) = 2 h

\frac{d}{d h} (2 h) = 2

\frac{d}{d h} (5) = 0

= \frac{1}{8} (2 h - 2 + 0)

Simplify

\frac{1}{8} (2 h - 2 + 0) : \frac{h - 1}{4}

= \frac{h - 1}{4}

3 x^{\frac{1}{4}} (x^{3} - 5)

\int_{0}^{\infty} sin (5 x) d x

\frac{\partial}{\partial x} (e^{2 x} y)

\frac{\partial}{\partial x} (x^{2} + 4)

y = 8 x^{\frac{1}{2}} + 4 x^{\frac{3}{2}} + 4

What is the derivative of (h^2-2h+5)/8 ?
The derivative of (h^2-2h+5)/8 is (h-1)/4
What is the first derivative of (h^2-2h+5)/8 ?
The first derivative of (h^2-2h+5)/8 is (h-1)/4