What is the derivative of y=x^2-8x-6 ?

The derivative of y=x^2-8x-6 is 2x-8

What is the first derivative of y=x^2-8x-6 ?

The first derivative of y=x^2-8x-6 is 2x-8

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derivative of

y = x^{2} - 8 x - 6

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) - \frac{d}{d x} (6)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (6) = 0

= 2 x - 8 - 0

Simplify

= 2 x - 8

\frac{d y}{d x} = x e^{6 x - 5 y}

\frac{\partial}{\partial y} (e^{2 x})

\frac{d}{d x} (\frac{2 x - x ^{2}}{x})

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 40 cos (8 t)

y^{^{''}} + 5 y^{^{'}} + 3 y = 0

What is the derivative of y=x^2-8x-6 ?
The derivative of y=x^2-8x-6 is 2x-8
What is the first derivative of y=x^2-8x-6 ?
The first derivative of y=x^2-8x-6 is 2x-8