What is the derivative of dcos(t)+t^2sin(t) ?

The derivative of dcos(t)+t^2sin(t) is cos(t)

What is the first derivative of dcos(t)+t^2sin(t) ?

The first derivative of dcos(t)+t^2sin(t) is cos(t)

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derivative of

d cos (t) + t^{2} sin (t)

cos (t)

Solution steps

\frac{d}{dd} (d cos (t) + t^{2} sin (t))

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{dd} (d cos (t)) + \frac{d}{dd} (t^{2} sin (t))

\frac{d}{dd} (d cos (t)) = cos (t)

\frac{d}{dd} (t^{2} sin (t)) = 0

= cos (t) + 0

Simplify

= cos (t)

n \to \infty lim (\frac{6}{n})

\int \frac{3}{7 + 3 x} d x

x \to 1 lim (- 16 x^{2} + 92 x)

\int \frac{1}{( 100 - x ^{2} ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (2 x sin (9 x^{2} y))

What is the derivative of dcos(t)+t^2sin(t) ?
The derivative of dcos(t)+t^2sin(t) is cos(t)
What is the first derivative of dcos(t)+t^2sin(t) ?
The first derivative of dcos(t)+t^2sin(t) is cos(t)