What is the derivative of-ln(1-x) ?

The derivative of-ln(1-x) is 1/(1-x)

What is the first derivative of-ln(1-x) ?

The first derivative of-ln(1-x) is 1/(1-x)

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derivative of

- ln (1 - x)

\frac{1}{1 - x}

Solution steps

\frac{d}{d x} (- ln (1 - x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (1 - x))

Apply the chain rule:

\frac{1}{1 - x} \frac{d}{d x} (1 - x)

= \frac{1}{1 - x} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= - \frac{1}{1 - x} (- 1)

Simplify

= \frac{1}{1 - x}

x \to - \infty lim (\frac{x}{2})

\frac{d y}{d x} - tan (x) y = y^{3}, y (0) = 1

\int 5 x^{4} e^{x^{5}} d x

\frac{d}{d t} (t^{3} + t)

\frac{d}{d x} (x^{2} \cdot ln (x^{2}))

What is the derivative of-ln(1-x) ?
The derivative of-ln(1-x) is 1/(1-x)
What is the first derivative of-ln(1-x) ?
The first derivative of-ln(1-x) is 1/(1-x)