What is the derivative of 4x^3+4x ?

The derivative of 4x^3+4x is 12x^2+4

What is the first derivative of 4x^3+4x ?

The first derivative of 4x^3+4x is 12x^2+4

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\frac{d}{d x} (4 x^{3} + 4 x)

12 x^{2} + 4

Solution steps

\frac{d}{d x} (4 x^{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (4 x) = 4

= 12 x^{2} + 4

\frac{\partial}{\partial x} (\frac{x - 3 y}{x ^{2} + y ^{2}})

\int \frac{3 x - 1}{x ^{2} - x + 1} d x

\frac{d}{d x} (arctan (\frac{x}{1 + x}))

\int \frac{( 4 x ^{3} - 3 x ^{2} - 8 x )}{6 x} d x

x \to 0 lim (x^{2} sin (\frac{1}{x}))

What is the derivative of 4x^3+4x ?
The derivative of 4x^3+4x is 12x^2+4
What is the first derivative of 4x^3+4x ?
The first derivative of 4x^3+4x is 12x^2+4