What is the sum from n=0 to infinity of 1/(2^{n+1)} ?

The sum from n=0 to infinity of 1/(2^{n+1)} is converges

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sum from n=0 to infinity of 1/(2^{n+1)}

n = 0 \sum \infty \frac{1}{2 ^{n + 1}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{2 ^{n + 1}}

Apply Series Ratio Test:

converges

= converges

\int (3 x^{2} - 2 x)^{3} d x

\frac{d ^{2} y}{d x ^{2}} = x^{2}

\frac{d}{d x} (4 3 x^{2} + 9)

\int_{0}^{l n (3)} \frac{4 e ^{x}}{1 + e ^{2 x}} d x

x (9^{- 2 x})

What is the sum from n=0 to infinity of 1/(2^{n+1)} ?
The sum from n=0 to infinity of 1/(2^{n+1)} is converges