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Popular >

y^{'''}-y^'=0

Solution

y^{^{'''}} - y^{^{'}} = 0

Solution

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t}

Solution steps

y^{'''} (t) - y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t}

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t}

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Frequently Asked Questions (FAQ)

What is the solution for y^{'''}-y^'=0 ?
The solution for y^{'''}-y^'=0 is y=c_{1}+c_{2}e^{-t}+c_{3}e^t