What is the tangent of f(x)=2+cos(x),\at x= pi/2 ?

The tangent of f(x)=2+cos(x),\at x= pi/2 is y=-x+2+pi/2

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tangent of f(x)=2+cos(x),\at x= pi/2

tangent of

f (x) = 2 + cos (x), at x = \frac{π}{2}

y = - x + 2 + \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{2}, 2)

Find the slope of

f (x) = 2 + cos (x) : \frac{df ( x )}{d x} = - sin (x)

Compute the slope of

f (x) = 2 + cos (x)

x = \frac{π}{2} : m = - 1

Find the line with slope m=

- 1

and passing through

(\frac{π}{2}, 2) : y = - x + 2 + \frac{π}{2}

y = - x + 2 + \frac{π}{2}

\frac{d}{d x} (\frac{- 9}{x ^{2} + 81})

\frac{\partial}{\partial x} (x^{2} e^{- x})

\int \frac{1}{y ^{4} + 1} d y

\int_{- 2}^{2} y^{2} - 2 d y

\int e^{- s t + t}

What is the tangent of f(x)=2+cos(x),\at x= pi/2 ?
The tangent of f(x)=2+cos(x),\at x= pi/2 is y=-x+2+pi/2