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Popular >

y^'+4y=20,y(1)=30

Solution

y^{^{'}} + 4 y = 20, y (1) = 30

Solution

y = 5 + 25 e^{4 - 4 t}

Solution steps

y^{'} (t) + 4 y = 20

Solve linear ODE:

y = 5 + 25 e^{4 - 4 t}

y = 5 + 25 e^{4 - 4 t}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+4y=20,y(1)=30 ?
The solution for y^'+4y=20,y(1)=30 is y=5+25e^{4-4t}