What is (\partial)/(\partial y)(x^2ln(y)) ?

The answer to (\partial)/(\partial y)(x^2ln(y)) is (x^2)/y

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(\partial)/(\partial y)(x^2ln(y))

\frac{\partial}{\partial y} (x^{2} ln (y))

\frac{x ^{2}}{y}

Solution steps

\frac{\partial}{\partial y} (x^{2} ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= x^{2} \frac{1}{y}

Simplify

x^{2} \frac{1}{y} : \frac{x ^{2}}{y}

= \frac{x ^{2}}{y}

(1 + x^{16}) y^{^{'}} + 16 x^{15} y = 9 x^{13}

\frac{d}{d x} (e^{x} cos (2 x) + e^{x} sin (2 x))

\frac{d}{d x} (\frac{x + 2}{x + 1})

\int x^{2} e^{x^{2}} d x

\frac{\partial}{\partial y} (e^{x y} y)

What is (\partial)/(\partial y)(x^2ln(y)) ?
The answer to (\partial)/(\partial y)(x^2ln(y)) is (x^2)/y