What is the integral of 1/2 cos(1/2)t ?

The integral of 1/2 cos(1/2)t is 1/4 cos(1/2)t^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/2 cos(1/2)t

\int \frac{1}{2} cos (\frac{1}{2}) t d t

\frac{1}{4} cos (\frac{1}{2}) t^{2} + C

Solution steps

\int \frac{1}{2} cos (\frac{1}{2}) t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} cos (\frac{1}{2}) \cdot \int t d t

Apply the Power Rule

: \frac{t ^{2}}{2}

= \frac{1}{2} cos (\frac{1}{2}) \frac{t ^{2}}{2}

Simplify

\frac{1}{2} cos (\frac{1}{2}) \frac{t ^{2}}{2} : \frac{1}{4} cos (\frac{1}{2}) t^{2}

= \frac{1}{4} cos (\frac{1}{2}) t^{2}

Add a constant to the solution

= \frac{1}{4} cos (\frac{1}{2}) t^{2} + C

\frac{d}{d y} (e^{2 y} - y cos (x y))

e^{2 x}, 0

\frac{d}{d x} (x^{\frac{2}{3}} (x^{2} - 8))

(x + 6) e^{3 x} + 4

\int 2^{x} sin (x) d x

What is the integral of 1/2 cos(1/2)t ?
The integral of 1/2 cos(1/2)t is 1/4 cos(1/2)t^2+C