What is the derivative of 2tan(5x+e^{-3x}) ?

The derivative of 2tan(5x+e^{-3x}) is 10sec^2(5x)-3e^{-3x}

What is the first derivative of 2tan(5x+e^{-3x}) ?

The first derivative of 2tan(5x+e^{-3x}) is 10sec^2(5x)-3e^{-3x}

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\frac{d}{d x} (2 tan (5 x) + e^{- 3 x})

10 sec^{2} (5 x) - 3 e^{- 3 x}

Solution steps

\frac{d}{d x} (2 tan (5 x) + e^{- 3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 tan (5 x)) + \frac{d}{d x} (e^{- 3 x})

\frac{d}{d x} (2 tan (5 x)) = 10 sec^{2} (5 x)

\frac{d}{d x} (e^{- 3 x}) = - 3 e^{- 3 x}

= 10 sec^{2} (5 x) - 3 e^{- 3 x}

\frac{d}{d x} (x^{2 - 3 x} x^{2})

i = 1 \sum \infty i

x \to - 7 lim (\frac{- x ^{2}}{x + 7})

\int \frac{1}{( x + 7 ) ^{2}} d x

\int - 8 sin (8 x) d x

What is the derivative of 2tan(5x+e^{-3x}) ?
The derivative of 2tan(5x+e^{-3x}) is 10sec^2(5x)-3e^{-3x}
What is the first derivative of 2tan(5x+e^{-3x}) ?
The first derivative of 2tan(5x+e^{-3x}) is 10sec^2(5x)-3e^{-3x}