What is the integral of arccos(3x) ?

The integral of arccos(3x) is xarccos(3x)-1/3 sqrt(1-9x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of arccos(3x)

\int arccos (3 x) d x

x arccos (3 x) - \frac{1}{3} 1 - 9 x^{2} + C

Solution steps

\int arccos (3 x) d x

Apply Integration By Parts

: x arccos (3 x) - \int - \frac{3 x}{1 - 9 x ^{2}} d x

= x arccos (3 x) - \int - \frac{3 x}{1 - 9 x ^{2}} d x

\int - \frac{3 x}{1 - 9 x ^{2}} d x = \frac{1}{3} 1 - 9 x^{2}

= x arccos (3 x) - \frac{1}{3} 1 - 9 x^{2}

Add a constant to the solution

= x arccos (3 x) - \frac{1}{3} 1 - 9 x^{2} + C

\int (2 + x^{7})^{3} x^{6} d x

f (x) = 3 x^{3}

\int 6 x d x

y = \frac{x ^{2} + 9}{( 7 x - 1 ) ^{5}}

\frac{x ^{2}}{( 6 + x ) ^{5}}

What is the integral of arccos(3x) ?
The integral of arccos(3x) is xarccos(3x)-1/3 sqrt(1-9x^2)+C