What is the solution for (dy)/(dx)=x^3(1-y),y(0)=3 ?

The solution for (dy)/(dx)=x^3(1-y),y(0)=3 is y=1+2/(e^{\frac{x^4){4}}}

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(dy)/(dx)=x^3(1-y),y(0)=3

\frac{d y}{d x} = x^{3} (1 - y), y (0) = 3

y = 1 + \frac{2}{e ^{\frac{x ^{4}}{4}}}

Solution steps

\frac{d y}{d x} = x^{3} (1 - y)

Solve linear ODE:

y = 1 + \frac{2}{e ^{\frac{x ^{4}}{4}}}

y = 1 + \frac{2}{e ^{\frac{x ^{4}}{4}}}

\int_{- \infty}^{- 8} x^{- \frac{4}{3}} d x

\frac{d x}{d t} = 6 - \frac{6 x}{15}

x \to \infty lim (2 - \frac{1}{x})

\int \frac{4 x + 1}{x ^{2}} d x

y^{^{'}} = 3 + t - y, y (0) = 1

What is the solution for (dy)/(dx)=x^3(1-y),y(0)=3 ?
The solution for (dy)/(dx)=x^3(1-y),y(0)=3 is y=1+2/(e^{\frac{x^4){4}}}