What is the solution for y^'+2/t y=(cos(t))/(t^2) ?

The solution for y^'+2/t y=(cos(t))/(t^2) is y=(sin(t))/(t^2)+(c_{1})/(t^2)

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y^'+2/t y=(cos(t))/(t^2)

y^{^{'}} + \frac{2}{t} y = \frac{cos ( t )}{t ^{2}}

y = \frac{sin ( t )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

Solution steps

y^{'} (t) + \frac{2}{t} y = \frac{cos ( t )}{t ^{2}}

Solve linear ODE:

y = \frac{sin ( t )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

y = \frac{sin ( t )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

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What is the solution for y^'+2/t y=(cos(t))/(t^2) ?
The solution for y^'+2/t y=(cos(t))/(t^2) is y=(sin(t))/(t^2)+(c_{1})/(t^2)