What is the derivative of-2\sqrt[4]{x} ?

The derivative of-2\sqrt[4]{x} is -1/(2x^{3/4)}

What is the first derivative of-2\sqrt[4]{x} ?

The first derivative of-2\sqrt[4]{x} is -1/(2x^{3/4)}

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\frac{d}{d x} (- 2 4 x)

- \frac{1}{2 x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (- 2 4 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (4 x)

Apply radical rule:

n a = a^{\frac{1}{n}}

= - 2 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

- 2 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : - \frac{1}{2 x ^{\frac{3}{4}}}

= - \frac{1}{2 x ^{\frac{3}{4}}}

\frac{d}{d x} (5 x - \frac{9}{x})

\int \frac{ln ( x - 1 )}{( x - 1 ) ^{2}} d x

\int \frac{25}{x ^{\frac{1}{2}}} d x

(csc (x) - cot (x))^{- 1}

f (x) = \frac{1}{x ^{4}}, (1, 1)

What is the derivative of-2\sqrt[4]{x} ?
The derivative of-2\sqrt[4]{x} is -1/(2x^{3/4)}
What is the first derivative of-2\sqrt[4]{x} ?
The first derivative of-2\sqrt[4]{x} is -1/(2x^{3/4)}