What is the solution for derivative of y+4yx^4=0 ?

The solution for derivative of y+4yx^4=0 is y=e^{-(4x^5)/5+c_{1}}

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derivative of y+4yx^4=0

\frac{d}{d x} y + 4 y x^{4} = 0

y = e^{- \frac{4 x ^{5}}{5} + c_{1}}

Solution steps

\frac{d y}{d x} + 4 y x^{4} = 0

Solve separable ODE:

y = e^{- \frac{4 x ^{5}}{5} + c_{1}}

y = e^{- \frac{4 x ^{5}}{5} + c_{1}}

\int x e^{- \frac{x}{3}} d x

(1.2) (3.4)

\frac{x}{e ^{x}}

\int \frac{( x ^{3} + 6 x ^{2} + 2 x + 3 )}{x ^{2} + 6 x + 1} d x

5 x y^{^{'}} + y = 30 x

What is the solution for derivative of y+4yx^4=0 ?
The solution for derivative of y+4yx^4=0 is y=e^{-(4x^5)/5+c_{1}}