What is (\partial)/(\partial x)(x^3-2x^2+y^3-2y) ?

The answer to (\partial)/(\partial x)(x^3-2x^2+y^3-2y) is 3x^2-4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^3-2x^2+y^3-2y)

\frac{\partial}{\partial x} (x^{3} - 2 x^{2} + y^{3} - 2 y)

3 x^{2} - 4 x

Solution steps

\frac{\partial}{\partial x} (x^{3} - 2 x^{2} + y^{3} - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (y^{3}) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y^{3}) = 0

\frac{\partial}{\partial x} (2 y) = 0

= 3 x^{2} - 4 x + 0 - 0

Simplify

= 3 x^{2} - 4 x

\frac{d}{d x} ((sin^{2} (x)) d x)

\int \frac{x ^{2} + 5 x ^{3} - 7}{x ^{2}} d x

\int \frac{9 x}{1 + x ^{4}} d x

x \to 2 - lim (x + 5)

\frac{5 x}{x + 3}

What is (\partial)/(\partial x)(x^3-2x^2+y^3-2y) ?
The answer to (\partial)/(\partial x)(x^3-2x^2+y^3-2y) is 3x^2-4x