What is the sum from n=0 to infinity of 6^{n+1} ?

The sum from n=0 to infinity of 6^{n+1} is diverges

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sum from n=0 to infinity of 6^{n+1}

n = 0 \sum \infty 6^{n + 1}

diverges

Solution steps

n = 0 \sum \infty 6^{n + 1}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty (- 1)^{n} e^{- n}

\int e^{9 x} cos (x) d x

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x \to 1 lim (1 - x)

\int \frac{3}{x ^{2}} cos (\frac{3}{x}) d x

What is the sum from n=0 to infinity of 6^{n+1} ?
The sum from n=0 to infinity of 6^{n+1} is diverges