What is the derivative of x^{1/(-3)} ?

The derivative of x^{1/(-3)} is -1/(3x^{4/3)}

What is the first derivative of x^{1/(-3)} ?

The first derivative of x^{1/(-3)} is -1/(3x^{4/3)}

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derivative of

x^{\frac{1}{- 3}}

- \frac{1}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (x^{\frac{1}{- 3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{- 3} x^{\frac{1}{- 3} - 1}

Simplify

\frac{1}{- 3} x^{\frac{1}{- 3} - 1} : - \frac{1}{3 x ^{\frac{4}{3}}}

= - \frac{1}{3 x ^{\frac{4}{3}}}

y = ln (x^{2} - 2)

\frac{d}{d x} (6 sin^{6} (x))

\int - 7 sin (7 x) d x

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What is the derivative of x^{1/(-3)} ?
The derivative of x^{1/(-3)} is -1/(3x^{4/3)}
What is the first derivative of x^{1/(-3)} ?
The first derivative of x^{1/(-3)} is -1/(3x^{4/3)}