What is (\partial)/(\partial x)(2x^{0.3}y^{0.3}) ?

The answer to (\partial)/(\partial x)(2x^{0.3}y^{0.3}) is (0.6y^{0.3})/(x^{0.7)}

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(\partial)/(\partial x)(2x^{0.3}y^{0.3})

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3})

\frac{0.6 y ^{0.3}}{x ^{0.7}}

Solution steps

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{0.3} \frac{\partial}{\partial x} (x^{0.3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y^{0.3} \cdot 0.3 x^{0.3 - 1}

Simplify

2 y^{0.3} \cdot 0.3 x^{0.3 - 1} : \frac{0.6 y ^{0.3}}{x ^{0.7}}

= \frac{0.6 y ^{0.3}}{x ^{0.7}}

\int r^{2} sec^{2} (r^{3}) d r

- 6 + 250 x^{3} - 3 x^{5}

y = 7 + 4 x^{2} - 2 x^{3}

\frac{d ^{2}}{d x ^{2}} (x^{3} - 3 x)

\frac{x ^{2} - 3 x}{x + 1}

What is (\partial)/(\partial x)(2x^{0.3}y^{0.3}) ?
The answer to (\partial)/(\partial x)(2x^{0.3}y^{0.3}) is (0.6y^{0.3})/(x^{0.7)}