What is the derivative of x^2+x+10 ?

The derivative of x^2+x+10 is 2x+1

What is the first derivative of x^2+x+10 ?

The first derivative of x^2+x+10 is 2x+1

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\frac{d}{d x} (x^{2} + x + 10)

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (10)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (10) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

f (x) = 100 x^{5}

\frac{5}{( s - 3 ) ^{3}}

\int x (x + 5)^{6} d x

\frac{\partial}{\partial x} (2 x y - e^{x})

\frac{\partial}{\partial y} (\frac{t ^{2}}{4 y ^{4}})

What is the derivative of x^2+x+10 ?
The derivative of x^2+x+10 is 2x+1
What is the first derivative of x^2+x+10 ?
The first derivative of x^2+x+10 is 2x+1