What is the sum from n=1 to infinity of 1/(n^0) ?

The sum from n=1 to infinity of 1/(n^0) is diverges

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sum from n=1 to infinity of 1/(n^0)

n = 1 \sum \infty \frac{1}{n ^{0}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0}}

Simplify

= n = 1 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

x \frac{d y}{d x} + 4 y = x^{3} - x

(1.3) (4.2)

y \frac{d y}{d t} = 2 t + 7

y = x^{\frac{2}{x}}

1 t

What is the sum from n=1 to infinity of 1/(n^0) ?
The sum from n=1 to infinity of 1/(n^0) is diverges