What is (\partial)/(\partial x)((sin(y))u(x,pi)) ?

The answer to (\partial)/(\partial x)((sin(y))u(x,pi)) is sin(y)u(,pi1)

Popular >

(\partial)/(\partial x)((sin(y))u(x,pi))

\frac{\partial}{\partial x} ((sin (y)) u (x, π))

sin (y) u (, π 1)

Solution steps

\frac{\partial}{\partial x} ((sin (y)) u (x, π))

Treat

y, u

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) u \frac{\partial}{\partial x} (x, π)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) u (, π \frac{\partial}{\partial x} (x))

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= sin (y) u (, π 1)

\int_{0}^{\frac{3}{2}} \frac{1}{36 + 16 x ^{2}} d x

\frac{1}{( 16 x ^{2} )}, x, \frac{x}{6}

j = 0 \sum \infty \frac{7}{5 ^{j}}

\frac{d}{d x} (\frac{x}{cos ( x )})

\frac{\partial}{\partial x} (x e^{4 x + 2 y})

What is (\partial)/(\partial x)((sin(y))u(x,pi)) ?
The answer to (\partial)/(\partial x)((sin(y))u(x,pi)) is sin(y)u(,pi1)