What is (\partial)/(\partial x)(-xy^2+xy) ?

The answer to (\partial)/(\partial x)(-xy^2+xy) is -y^2+y

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(\partial)/(\partial x)(-xy^2+xy)

\frac{\partial}{\partial x} (- x y^{2} + x y)

- y^{2} + y

Solution steps

\frac{\partial}{\partial x} (- x y^{2} + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x y^{2}) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

\frac{\partial}{\partial x} (x y) = y

= - y^{2} + y

\frac{d}{d x} (\frac{x}{x - 1})

x^{2} y^{^{'}} + 2 x y = 5 y^{4}

\frac{\partial}{\partial x} (x^{3} + 2^{y} + x^{y})

\frac{\partial}{\partial x} (5 x y^{5} z)

\frac{d}{d x} (x e^{6 x})

What is (\partial)/(\partial x)(-xy^2+xy) ?
The answer to (\partial)/(\partial x)(-xy^2+xy) is -y^2+y