What is (\partial)/(\partial x)(4x^2-2y^2) ?

The answer to (\partial)/(\partial x)(4x^2-2y^2) is 8x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x^2-2y^2)

\frac{\partial}{\partial x} (4 x^{2} - 2 y^{2})

8 x

Solution steps

\frac{\partial}{\partial x} (4 x^{2} - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{2}) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 8 x - 0

Simplify

= 8 x

\int sec (θ) d θ

(2 x + 1 + 6 y) d x + 3 d y = 0

\int 4 sin (x) - 1 + 8 x - 5 d x

n = 1 \sum \infty \frac{n !}{2 ^{n}}

\int 7 e^{6 x} d x

What is (\partial)/(\partial x)(4x^2-2y^2) ?
The answer to (\partial)/(\partial x)(4x^2-2y^2) is 8x