What is the tangent of y=e^{4x}cos(pix),(0,1) ?

The tangent of y=e^{4x}cos(pix),(0,1) is y=4x+1

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tangent of y=e^{4x}cos(pix),(0,1)

tangent of

y = e^{4 x} cos (π x), (0, 1)

y = 4 x + 1

Solution steps

Find the slope of

y = e^{4 x} cos (π x) : \frac{d y}{d x} = 4 e^{4 x} cos (π x) - π e^{4 x} sin (π x)

Compute the slope of

y = e^{4 x} cos (π x)

(0, 1) : m = 4

Find the line with slope m=

4

and passing through

(0, 1) : y = 4 x + 1

y = 4 x + 1

\frac{d}{d x} (e^{0.5 x})

\frac{d}{d x} (\frac{4 x ^{3} - 5 x ^{2}}{3 x ^{2} - 4})

\int_{- 1}^{1} (20 - 12 x)^{- 1} d x

\int \frac{( sin ( 2 x ) )}{e ^{x}} d x

\int \frac{( x ^{2} + 5 x + 1 )}{( x ^{2} + 1 ) ^{2}} d x

What is the tangent of y=e^{4x}cos(pix),(0,1) ?
The tangent of y=e^{4x}cos(pix),(0,1) is y=4x+1