What is the derivative of f(x)=-4/3 x^{2/3} ?

The derivative of f(x)=-4/3 x^{2/3} is -8/(9x^{1/3)}

What is the first derivative of f(x)=-4/3 x^{2/3} ?

The first derivative of f(x)=-4/3 x^{2/3} is -8/(9x^{1/3)}

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derivative of

f (x) = - \frac{4}{3} x^{\frac{2}{3}}

- \frac{8}{9 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (- \frac{4}{3} x^{\frac{2}{3}})

Simplify

- \frac{4}{3} x^{\frac{2}{3}} : - \frac{4 x ^{\frac{2}{3}}}{3}

= \frac{d}{d x} (- \frac{4 x ^{\frac{2}{3}}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{4}{3} \frac{d}{d x} (x^{\frac{2}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{4}{3} \cdot \frac{2}{3} x^{\frac{2}{3} - 1}

Simplify

- \frac{4}{3} \cdot \frac{2}{3} x^{\frac{2}{3} - 1} : - \frac{8}{9 x ^{\frac{1}{3}}}

= - \frac{8}{9 x ^{\frac{1}{3}}}

(y^{2} + 1) d x = y \cdot sec^{2} (x) d y

f (x) = \frac{x ^{2}}{3 + x}

y^{^{'}} + \frac{1}{x} y = 8 x^{2}

\frac{d}{d x} (arctan (x + 1))

\int \frac{x ^{2}}{x ^{3}} + 5 d x

What is the derivative of f(x)=-4/3 x^{2/3} ?
The derivative of f(x)=-4/3 x^{2/3} is -8/(9x^{1/3)}
What is the first derivative of f(x)=-4/3 x^{2/3} ?
The first derivative of f(x)=-4/3 x^{2/3} is -8/(9x^{1/3)}