What is (\partial)/(\partial x)((7x)/(4+x^2+y^2)) ?

The answer to (\partial)/(\partial x)((7x)/(4+x^2+y^2)) is (7(-x^2+y^2+4))/((4+x^2+y^2)^2)

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(\partial)/(\partial x)((7x)/(4+x^2+y^2))

\frac{\partial}{\partial x} (\frac{7 x}{4 + x ^{2} + y ^{2}})

\frac{7 ( - x ^{2} + y ^{2} + 4 )}{( 4 + x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{7 x}{4 + x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial x} (\frac{x}{4 + x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 7 \cdot \frac{\frac{\partial}{\partial x} ( x ) ( 4 + x ^{2} + y ^{2} ) - \frac{\partial}{\partial x} ( 4 + x ^{2} + y ^{2} ) x}{( 4 + x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (4 + x^{2} + y^{2}) = 2 x

= 7 \cdot \frac{1 \cdot ( 4 + x ^{2} + y ^{2} ) - 2 xx}{( 4 + x ^{2} + y ^{2} ) ^{2}}

Simplify

7 \cdot \frac{1 \cdot ( 4 + x ^{2} + y ^{2} ) - 2 xx}{( 4 + x ^{2} + y ^{2} ) ^{2}} : \frac{7 ( - x ^{2} + y ^{2} + 4 )}{( 4 + x ^{2} + y ^{2} ) ^{2}}

= \frac{7 ( - x ^{2} + y ^{2} + 4 )}{( 4 + x ^{2} + y ^{2} ) ^{2}}

(lo g_{10} (1 + x))^{^{'}}

- 8 x

\int sin (x) - sin^{3} (x) d x

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\int (\frac{x ^{2} + 2 x + 1}{x ^{2}}) d x

What is (\partial)/(\partial x)((7x)/(4+x^2+y^2)) ?
The answer to (\partial)/(\partial x)((7x)/(4+x^2+y^2)) is (7(-x^2+y^2+4))/((4+x^2+y^2)^2)