What is the solution for (9y^2-xy)dx+(x^2)dy=0 ?

The solution for (9y^2-xy)dx+(x^2)dy=0 is y= x/(9ln(x)+c_{1)}

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(9y^2-xy)dx+(x^2)dy=0

(9 y^{2} - x y) d x + (x^{2}) d y = 0

y = \frac{x}{9 ln ( x ) + c _{1}}

Solution steps

(9 y^{2} - x y) d x + (x^{2}) d y = 0

Solve Bernoulli ODE:

y = \frac{x}{9 ln ( x ) + c _{1}}

y = \frac{x}{9 ln ( x ) + c _{1}}

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n = 0 \sum \infty \frac{1}{2} (\frac{1}{2})^{n}

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What is the solution for (9y^2-xy)dx+(x^2)dy=0 ?
The solution for (9y^2-xy)dx+(x^2)dy=0 is y= x/(9ln(x)+c_{1)}