What is derivative of f(x)=8cos(t) ?

The answer to derivative of f(x)=8cos(t) is (dt)/(dx)=0

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derivative of f(x)=8cos(t)

derivative of

f (x) = 8 cos (t)

\frac{d t}{d x} = 0

Solution steps

f (x) = 8 cos (t)

Treat

t

t (x)

Differentiate both sides:

0 = - 8 sin (t) \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

x \to 16 lim (\frac{sin ( x )}{x})

x y^{^{'}} - 2 y = - 2 x^{2} + 2 x - 2

\int_{0}^{4} (2 x + 4) d x

(2 x^{2} + 1) 3 (x^{2} - 4) 2

\int \frac{cos ^{2} ( x ) sin ( x )}{2} d x

What is derivative of f(x)=8cos(t) ?
The answer to derivative of f(x)=8cos(t) is (dt)/(dx)=0