What is the integral of (ln(x^{18}))/x ?

The integral of (ln(x^{18}))/x is 9ln^2(x)+C

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integral of (ln(x^{18}))/x

\int \frac{ln ( x ^{18} )}{x} d x

9 ln^{2} (x) + C

Solution steps

\int \frac{ln ( x ^{18} )}{x} d x

Simplify

ln (x^{18}) : 18 ln (x)

= \int \frac{18 ln ( x )}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int \frac{ln ( x )}{x} d x

Apply u-substitution

: \int u d u

= 18 \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= 18 \cdot \frac{u ^{2}}{2}

Substitute back

u = ln (x)

= 18 \cdot \frac{ln ^{2} ( x )}{2}

Simplify

18 \cdot \frac{ln ^{2} ( x )}{2} : 9 ln^{2} (x)

= 9 ln^{2} (x)

Add a constant to the solution

= 9 ln^{2} (x) + C

\int (2 x^{3} - 4 x + 3 x) d x

\frac{\partial}{\partial y} (\frac{x ^{2} y}{x ^{2} + y ^{2}})

\frac{d y}{d x} = \frac{e ^{- 2 x}}{1 + e ^{- 2 x}}

10 cos (x)

\int x e^{- \frac{1}{2} x^{2}} d x

What is the integral of (ln(x^{18}))/x ?
The integral of (ln(x^{18}))/x is 9ln^2(x)+C