What is the solution for (dx)/(dt)= 1/(x+t+1) ?

The solution for (dx)/(dt)= 1/(x+t+1) is x=-\W((c_{1})/(e^{t+2)})-t-2

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(dx)/(dt)= 1/(x+t+1)

\frac{d x}{d t} = \frac{1}{x + t + 1}

x = - W (\frac{c _{1}}{e ^{t + 2}}) - t - 2

Solution steps

\frac{d x}{d t} = \frac{1}{x + t + 1}

Solve exact ODE:

x = - W (\frac{c _{1}}{e ^{t + 2}}) - t - 2

x = - W (\frac{c _{1}}{e ^{t + 2}}) - t - 2

(2, 1), (5, 7)

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\frac{d}{d x} (6 - arcsin (\frac{x}{x ^{2} + 4}))

\int (3 x^{2} - 4 x^{3}) d x

x y^{^{'}} + 3 y^{^{'}} - (x + 3) cos (x) + y = 0

What is the solution for (dx)/(dt)= 1/(x+t+1) ?
The solution for (dx)/(dt)= 1/(x+t+1) is x=-\W((c_{1})/(e^{t+2)})-t-2