What is the sum from n=0 to infinity of 1-cos(1/n) ?

The sum from n=0 to infinity of 1-cos(1/n) is converges

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sum from n=0 to infinity of 1-cos(1/n)

n = 0 \sum \infty 1 - cos (\frac{1}{n})

converges

Solution steps

n = 1 \sum \infty 1 - cos (\frac{1}{n})

Apply Series Integral Test:

converges

= converges

y^{^{''}} - 6 y^{^{'}} + 9 y = \frac{( e ^{3 t} )}{t ^{2}}

f (x) = \frac{2 x ^{2} + 2 x - 4}{x ^{2} + x - 6}

\frac{d}{d x} (2 (e^{- x} - e^{- x} x))

x \to \infty lim (\frac{x}{28})

\frac{\partial}{\partial x} (5 x^{3} y^{6})

What is the sum from n=0 to infinity of 1-cos(1/n) ?
The sum from n=0 to infinity of 1-cos(1/n) is converges