What is (\partial)/(\partial x)(2y-x) ?

The answer to (\partial)/(\partial x)(2y-x) is -1

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(\partial)/(\partial x)(2y-x)

\frac{\partial}{\partial x} (2 y - x)

- 1

Solution steps

\frac{\partial}{\partial x} (2 y - x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 1

Simplify

= - 1

6 - t

\frac{d}{d x} (\frac{- ( x + 1 )}{( x - 1 ) ^{3}})

\int cos^{4} (7 x + 3) d x

\frac{d y}{d x} = 4 y + a

t^{2} e^{- 4 t}

What is (\partial)/(\partial x)(2y-x) ?
The answer to (\partial)/(\partial x)(2y-x) is -1